PHP Form: yeni bilgiler girerken yeni bir tablo satırı ekleyerek sonuçlar aldıktan sonra

1 Cevap

Although probarly quite simple, i cannot seem to find the following.
The form takes certain data, and then represents the data in a table.

Next step i click the hyperlink that takes me back to the form.
Now my question is how exactly do i make it possible when filling in the same form again so both results are displayed in the same table?
Then filling in a other form with data adds another row and so on.

Saygılar.

Aşağıdaki kodu (bu İngilizce olmadığını pardon).

<?php
session_start();
?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0            Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-Strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">

<head>
<title>ExpoFormulier</title>

<body>

<?php
if (!empty($_POST))
{
$standnaam = $_POST["standnaam"];
$oppervlakte = $_POST["oppervlakte"];
//value in the form van checkboxes op 1 zetten!
$verdieping = isset($_POST["verdieping"]) ? $_POST["verdieping"] : 0;  //if checkbox    checked value 1 anders 0
$telefoon = isset($_POST["telefoon"]) ? $_POST["telefoon"] : 0;  
$netwerk = isset($_POST["netwerk"]) ? $_POST["netwerk"] : 0; 


if (is_numeric($oppervlakte)) 
{
    $_SESSION["standnaam"]=$standnaam;
    $_SESSION["oppervlakte"]=$oppervlakte;
    $_SESSION["verdieping"]=$verdieping;
    $_SESSION["telefoon"]=$telefoon;
    $_SESSION["netwerk"]=$netwerk;
    header("Location:ExpoOverzicht.php"); //verzenden naar ExpoOverzicht.php dmv header
}
else 
{
    echo "<h1>Foute gegevens, Opnieuw invullen a.u.b</h1>";
}  
}

?>

<form action="<?php echo $_SERVER["PHP_SELF"]; ?>" method="post" id="form1">
<h1>Vul de gegevens in</h1>
<table>
    <tr>
        <td>Standnaam:</td>
        <td><input type="text" name="standnaam" size="18"/></td>
    </tr>
    <tr>
        <td>Oppervlakte (in m^2):</td>
        <td><input type="text" name="oppervlakte" size="6"/></td>
    </tr>
    <tr>
        <td>Verdieping:</td>
        <td><input type="checkbox" name="verdieping" value="1"/></td>
        <!--value op 1 zetten voor checkbox! indien checked is value 1 -->
    </tr>
    <tr>
        <td>Telefoon:</td>
        <td><input type="checkbox" name="telefoon" value="1"/></td>
    </tr>
    <tr>
        <td>Netwerk:</td>
        <td><input type="checkbox" name="netwerk" value="1"/></td>
    </tr>
    <tr>
        <td><input type="submit" name="verzenden" value="Verzenden"/></td>
    </tr>
</table>

</form>

İkinci Dosya:

<?php
session_start();
?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-Strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">

<head>
    <title>ExpoOverzicht</title>
 <meta http-equiv="content-type" content="text/html; charset=utf-8" />
    <link href="StyleSheetExpo.css" rel="stylesheet" type="text/css" />  
</head>

<body>

<h1>Overzicht van de ingegeven standen in deze sessie</h1>

<?php

$standnaam = $_SESSION["standnaam"];
$oppervlakte = $_SESSION["oppervlakte"];
$verdieping = $_SESSION["verdieping"];
$telefoon = $_SESSION["telefoon"];
$netwerk = $_SESSION["netwerk"];

$result1 = 0; //telkens declaren anders fout "undefined variable"
$result2 = 0;
$result3 = 0;
$prijsCom = 0;
$prijsVerdieping = 0;

for ($i=1; $i <= $oppervlakte; $i++)
{   
    if($i <= 10)
    {
       $tarief1 = 1 * 100;
       $result1 += $tarief1;
    }

    if($i > 10 && $i <= 30)
    {
        $tarief2 = 1 * 90;
        $result2 += $tarief2;      
    }

    if($i > 30)
    {
        $tarief3 = 1 * 80;
        $result3 += $tarief3;
    }  
}
$prijsOpp = $result1 + $result2 + $result3;


if($verdieping == 1)
{
    $prijsVerdieping = $oppervlakte * 120;
}


if(($telefoon == 1) || ($netwerk == 1)) // eerst deze OR conditie  of anders gebruikt de code alleen nog maar 20
{
    $prijsCom = 20;
}

if(($telefoon == 1) && ($netwerk == 1))
{
    $prijsCom = 30;
}


$totalePrijs = $prijsOpp + $prijsVerdieping + $prijsCom; 

echo "<table class=\"tableExpo\">";

    echo "<th>Standnaam</th>";
    echo "<th>Oppervlakte</th>";
    echo "<th>Verdieping</th>";
    echo "<th>Telefoon</th>";
    echo "<th>Netwerk</th>";
    echo "<th>Totale prijs</th>";

        echo "<tr>";     
            echo "<td>".$standnaam."</td>";
            echo "<td>".$oppervlakte."</td>";
            echo "<td>".$verdieping."</td>";
            echo "<td>".$telefoon."</td>";
            echo "<td>".$netwerk."</td>";
            echo "<td>".$totalePrijs."</td>";
        echo "</tr>";

echo "</table>";

?>

<a href="ExpoFormulier.php">Terug naar het formulier</a>

</body>
</html>

</body>
</html>

1 Cevap

Sizin oturum değişkenleri sadece girilen verilerin son parça saklamak olacaktır. Oldukça basit değişkenler olarak oturumda bunları depolamak yerine, oturumda bir dizi koyarak deneyin. Sonra form tekrar gönderildiğinde, bu diziler için başka bir girdi ekleyin. Bu şekilde daha önce orada ne üzerine yazmaz.

ETA:

Eğer oturum değişkenleri set nerede Page 1, bu deneyin:

$_SESSION["standnaam"][]=$standnaam;
$_SESSION["oppervlakte"][]=$oppervlakte;
$_SESSION["verdieping"][]=$verdieping;
$_SESSION["telefoon"][]=$telefoon;
$_SESSION["netwerk"][]=$netwerk;

Sayfa 2, tablo satırları yazmak nerede, bu deneyin:

for($i = 0; $i < count($standnaam); $i++) {
    echo "<tr>";     
        echo "<td>".$standnaam[$i]."</td>";
        echo "<td>".$oppervlakte[$i]."</td>";
        echo "<td>".$verdieping[$i]."</td>";
        echo "<td>".$telefoon[$i]."</td>";
        echo "<td>".$netwerk[$i]."</td>";
        echo "<td>".$totalePrijs[$i]."</td>";
    echo "</tr>";
}

Ben dokunsa bunu düşünüyorum.