PHP - karşılaştırma bir kötü sonuç

0 Cevap php

I have a function that connects to the database and returns a number and a second function, which returns the size of a file. If I use the echo function to view the results functions: variable1 = 1345064, and variable2 = 135

Ben bir karşılaştırma kullandığınızda, ancak, bana yanlış sonuç gidin:

if($variable1 < $variable2)

{

   echo 'This code is displayed';

}

else

{

   echo 'This code should display';

}

Sorun ne?


Benim kaynak kodu:

<?php
include 'funkcje.inc';
    $login = $_GET['login'];
            $fsize = WielkoscPliku2($file);

    $tmp = $fsize / 1000000;

$zmienna1 = SprTransfer($login);
$zmienna2 = floor($tmp);

      if($zmienna1 < $zmienna2)
    {
        echo "This code is displayed";  
    }
    else
    {
            echo "This code should be displayed";
         }
    ?>

SprTransfer fonksiyonu:

<?php
require "connection.php";
connection(); 

...

function SprTransfer($login)
{
$zapytanie = "SELECT `transfer` FROM `uzytkownicy` WHERE `nick`='$login'";
    $idzapytania = mysql_query($zapytanie);
    $sprwaznosc = mysql_fetch_row($idzapytania);
    return $sprwaznosc[0];
}
?>

Ana dosya:

include 'funkcje.inc';

    $login = $_GET['login'];

            $fsize = WielkoscPliku2($file);


    $tmp = $fsize / 1000000;


$zmienna1 = SprTransfer($login);

$zmienna2 = floor($tmp);


      if($zmienna1 < $zmienna2)

    {

        echo "This code is displayed";



    }

    else

    {

            echo "This code should be displayed";

         }




function.inc file:


require "connection.php";

connection(); 



function SprTransfer($login)

{

$zapytanie = "SELECT `transfer` FROM `uzytkownicy` WHERE `nick`='$login'";

    $idzapytania = mysql_query($zapytanie);

    $sprwaznosc = mysql_fetch_row($idzapytania);

    return $sprwaznosc[0];


}

0 Cevap