i am writing code of pagination & i got an error. this is my code :

<?php 
mysql_connect("localhost", "root", "") or die(mysql_error()); 
mysql_select_db("Admin") or die(mysql_error()); 

if (isset($_GET["page"]))
 {
 $page  = $_GET["page"]; 
 }
 else
 {
 $page=1;
 }



$start_from = ($page-1) * 2; 
$sql = "SELECT * FROM events ORDER BY event ASC LIMIT $start_from, 2"; 
$result = mysql_query ($sql) or die(mysql_error()); 
$num=mysql_numrows($result);
$x=0;
?> 
<table>
<tr><td>Event</td><td>Types</td></tr>
<?php 
while ($x<$num) {
$row1 = mysql_result($result,$x,'event');
$row2 = mysql_result($result,$x,'types'); 
?> 
            <tr>
            <td><? echo $row1; ?></td>
            <td><? echo $row2; ?></td>
            </tr>
<?php 
$x++;
} 
?> 
</table>
<?php 
$sql = "SELECT COUNT(event) FROM events"; 
$result = mysql_query($sql) or die(mysql_error()); 
$row = mysql_fetch_row($result); 
$total_records = $row[0]; 
$total_pages = ceil($total_records / 2); 

for ($i=1; $i<=$total_pages; $i++) { 
            echo "<a href='pagination.php?page=".$i."'>".$i."</a> "; 
}

?>

şimdi ben bir hata var.

  object not found