Benim php Sorguda hata alıyorum

0 Cevap php

Benim php sorguda bir hata mesajı alıyorum.

Error being displayed: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1294251744','127.0.0.1','/register')' at line 2

benim kod:

<?php 
require_once("includes/database.php"); 

//Set timeout to 5 minutes
$timeoutseconds  =  300 ;

//get the time 
$timestamp  =  time();
//Delete all users that are no online after the time out allowed
$timeout  =  $timestamp - $timeoutseconds ;

// stores users IP addresss 
$user_ip = $_SERVER['REMOTE_ADDR'];
// Automatically collects the hostname or domain  like example.com) 
$host  = $_SERVER['HTTP_HOST'];
$host_upper = strtoupper($host);
$path   = rtrim(dirname($_SERVER['PHP_SELF']), '/');

//insert the values
$sql = "INSERT INTO totalonline(timestamp, ip, file)
            VALUES (''$timestamp','$user_ip','$path')";

    $result = mysql_query($sql, $conndb) or die(mysql_error());


//delete values when they leave
mysql_query("DELETE FROM totalonline WHERE timestamp < $timeout");

//grab the results
$sql = "SELECT DISTINCT ip FROM totalonline WHERE file='$path' ";

    $result = mysql_query($sql, $conndb) or die(mysql_error());

//number of rows = the number of people online 
    $user = mysql_num_rows($result);


//spit out the results 

if( $user  ==  1 ) { 
echo "$user User online"; 
} else { 
echo "$user User online"; 
} 

?>

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