Javascript dizi PHP dizi dönen

0 Cevap php

I am trying to return my SQL query array into a javascript array and then display the info one at a time. I have found a few helpful posts already on here but I still cannot get it to work. I am new to ajax and so please forgive any stupid mistakes. Below is the php followed by a description. php: this is in an external file from index.php

<?php
include('connection.php');

$query = "SELECT * FROM photos";
$queryresult = mysql_query($query);

while ( $line = mysql_fetch_array($result) ) {
    $path[] = $row[0];
}
$paths = json_encode($path);
header('Content-type: application/json');
echo $paths;
?>

Bu sonuçlar (onlar dosya yolları vardır) dizi alır ve json javascript geçmek için kodlar. Connection.php doğru ve çalışıyor.

HTML / Javascript:

<html>
<head>
<script src="JavaScript/gjs.js" type="text/javascript"></script>
<script src="jquery/jquery-1.4.3.min.js" type="text/javascript"></script>
<script>
function imageload(){
var i = 1;
$.getJSON('phpfiles/getpiccode.php', function(data) {

    var can = document.getElementById('canvas').getContext('2d');

    $.each(data,function(idx, row){
    var img = new Image();
    img.onload = function(){
        can.drawImage(img, 0, 0, 1280, 800);
    }
    img.src = row;
            i++;
});

});

}
</script>
</head>

<body>
<div class="container">
<canvas id="canvas" class="canvas-one" width="1280" height="800">
<script>imageload();</script>This text is displayed if your browser does not support HTML5 Canvas</canvas>
</div>

</body>
</html>

Ben mantıklı umuyoruz. Tekrar teşekkürler!

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